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Table 3 Overview and relationships of approaches to quantify prolonged hospital stay associated with nosocomial infections

From: Estimands to quantify prolonged hospital stay associated with nosocomial infections

Approach

real data example (SIR-3 study)

 

\(\hat {\lambda }_{01}=124/6442 \approx 0.0192\)

 

\(\hat {\lambda }_{02}=(756-124)/6442 \approx 0.0981\)

 

\(\hat {\lambda }_{12}=124/1527 \approx 0.0812\)

\(A_{1}=\frac {1}{\lambda _{12}}\)

12.31 days

\(A_{2}=\frac {1} {\lambda _{12}} - \frac {1}{\lambda _{02}}\)

2.12 days

\(A_{3}=\frac {\lambda _{01}}{\lambda _{01}+\lambda _{02}} \times \frac {1}{\lambda _{12}} \times \frac {(\lambda _{02}-\lambda _{12})} {\lambda _{02}}\)

0.35 days

\(A_{4}=(\frac {\lambda _{02}} {\lambda _{12}}-1) \times \frac {1}{\lambda _{01}+\lambda _{02}}\)

1.77 days

Additive relationships between approaches (differences)

\(A_{1}-A_{4}=\frac {1}{\lambda _{12}} \times \frac {\lambda _{01}+\lambda _{12}}{\lambda _{01}+\lambda _{02}}\)

10.54 days

\(A_{1}-A_{3}=\frac {1}{\lambda _{02}} \times \frac {\lambda _{02}^{2}+\lambda _{12}\lambda _{01}} {\lambda _{12}\lambda _{02}+\lambda _{12}\lambda _{01}}\)

11.97 days

\(A_{1} - A_{2}=\frac {1}{\lambda _{02}}\)

10.19 days

\(A_{4}-A_{3}=\frac {\lambda _{02}-\lambda _{01}}{\lambda _{02}} \times \frac {\lambda _{02}-\lambda _{12}}{\lambda _{12}(\lambda _{01}+\lambda _{02})} \)

1.43 days

\(A_{2}-A_{3}=A_{4}=\frac {\lambda _{02}-\lambda _{12}}{\lambda _{12}(\lambda _{01}+\lambda _{02})}\)

1.77 days

\(A_{2} - A_{4}=A_{3}=\frac {\lambda _{01}}{\lambda _{02}}\times \frac {\lambda _{02}-\lambda _{12}}{\lambda _{12}(\lambda _{01}+\lambda _{02})} \)

0.35 days

Following relationship holds: A3+A4=A2

Multiplicative relationships between approaches (ratios)

\(\frac {A_{1}}{A_{4}}=\frac {\lambda _{01}+\lambda _{02}}{\lambda _{02}-\lambda _{12}} \ge 1\)

6.94

\(\frac {A_{1}}{A_{3}}=\frac {\lambda _{02}(\lambda _{01}+\lambda _{02})} {\lambda _{01}(\lambda _{02}-\lambda _{12})} \ge 1\)

35.4

\(\frac {A_{1}}{A_{2}}=\frac {\lambda _{02}}{\lambda _{02}-\lambda _{12}} \ge 1\)

5.80

\(\frac {A_{3}}{A_{4}}=\frac {\lambda _{01}}{\lambda _{02}}= \text {odds(NI)} \)

0.196

\(\frac {A_{3}}{A_{2}}=\frac {\lambda _{01}}{\lambda _{01}+\lambda _{02}}=\text {risk(NI)} \le 1\)

0.164

\(\frac {A_{2}}{A_{4}}=\frac {\lambda _{01}+\lambda _{02}}{\lambda _{02}}=\frac {\text {odds(NI)}}{\text {risk(NI)}} \ge 1\)

1.20

Following relationship holds if λ01λ02:A3A4A2A1